ÌâÄ¿ÄÚÈÝ

ÏÂÁзûºÅÖУ¬±íʾ2¸öÇâ·Ö×ÓµÄÊÇ

A. H2 B. 2H C. 2H2 D. 2H+

C ¡¾½âÎö¡¿¡¾½âÎö¡¿ A¡¢¸ù¾Ý±êÔÚÔªËØ·ûºÅÓÒϽǵÄÊý×Ö±íʾһ¸ö·Ö×ÓÖÐËùº¬Ô­×ӵĸöÊý£»Òò´ËH2±íʾһ¸öÇâ·Ö×Ó£¬¹ÊA²»·ûºÏÌâÒ⣻ B¡¢¸ù¾Ý±êÔÚÔªËØ·ûºÅÇ°ÃæµÄÊý×Ö±íʾԭ×ӵĸöÊý£»ËùÒÔ2H±íʾ2¸öÇâÔ­×Ó£¬¹ÊB²»·ûºÏÌâÒ⣻ C¡¢¸ù¾Ý±êÔÚ»¯Ñ§Ê½Ç°ÃæµÄÊý×Ö±íʾ·Ö×ӵĸöÊý£»ËùÒÔ2H2±íʾ2¸öÇâ·Ö×Ó£¬¹ÊC·ûºÏÌâÒ⣻ D¡¢¸ù¾Ý±êÔÚÀë×Ó·ûºÅÇ°ÃæµÄÊý×Ö±íʾÀë×Ó¸öÊý£»ËùÒÔ2H+±íʾ2¸öÇâÀë×Ó£¬¹ÊD...
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¹¤ÒµÉÏÉú²úµçʯ(CaC2)ÖÆ±¸ÖØÒª¹¤ÒµÔ­ÁÏÒÒȲ(CxHy)Á÷³ÌÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)д³ö̼Ëá¸Æ¸ßηֽâ¢ÙµÄ»¯Ñ§·½³Ìʽ____________________£»B¡¢C×é³ÉµÄÔªËØÏàͬ£¬CÓж¾£¬Ôò·´Ó¦¢ÚµÄ»¯Ñ§·½³Ìʽ____________________£»¸ù¾Ý·´Ó¦¢Û¿ÉÍÆ¶Ï¹ÌÌåDÖÐÒ»¶¨º¬ÓеÄÔªËØÊÇ____________________¡£

(2)ÒÑÖª£ºÅ¨ÁòËá¾ßÓÐÇ¿ÎüË®ÐÔ¡£Ò»¸öÒÒȲ·Ö×ÓÓÉ4¸öÔ­×Ó¹¹³É¡£ÎªÁ˲ⶨÒÒȲµÄ×é³É£¬½«Ò»¶¨Á¿µÄÒÒȲ(CxHy)ÍêȫȼÉÕ£¬²¢½«Éú³ÉµÄÆøÌ建»ºÍ¨¹ýÏÂͼµÄ__________(Ñ¡Ìî¡°¼×¡±»ò¡°ÒÒ¡±)×°Öã¬ÔÙ»º»ºÍ¨¹ýÒ»¶Îʱ¼äµÄN2£¬»º»ºÍ¨¹ýÒ»¶Îʱ¼äµÄN2µÄÄ¿µÄÊÇ__________¡£

¼Ç¼ʵÑéÊý¾ÝÈçÏ£º

×°ÖÃ

·´Ó¦Ç°ÖÊÁ¿

·´Ó¦ºóÖÊÁ¿

ŨÁòËá

125.3g

127.1g

ŨÇâÑõ»¯ÄÆÈÜÒº

78.2g

87.0g

¸ù¾ÝʵÑéÊý¾ÝÍÆ¶ÏÒÒȲµÄ»¯Ñ§Ê½(д³öÍÆ¶Ï¹ý³Ì)£º__________

CaCO3CaO+CO2¡ü CaO+3CCaC2+CO¡ü ÒÒ Ê¹Éú³ÉµÄÆøÌåÍêÈ«±»ÎüÊÕ ÒÒȲÖÐÇâÔªËØµÄÖÊÁ¿£º£¨127.1g-125.3g£©¡Á=0.2g£¬ÒÒȲÖÐÌ¼ÔªËØµÄÖÊÁ¿£º£¨87.0g-78.2g£©¡Á=2.4g£¬¸ù¾ÝÌâÒâÓУº=£¬½âµÃ= C2H2 ¡¾½âÎö¡¿ (1)̼Ëá¸Æ¸ßηֽâµÄ»¯Ñ§·½³ÌʽΪ£ºCaCO3CaO+CO2¡ü£¬B¡¢C×é³ÉµÄÔªËØÏàͬ£¬CÓж¾£¬ÔòCÊÇCO£¬BÊÇCO2¡£»¯Ñ§·´Ó¦Ç°ºóÔªËØÖÖ...

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø