ÌâÄ¿ÄÚÈÝ

¼×ͬѧÔÚʵÑéÊÒ×öÖкͷ´Ó¦Ê±£¬½«Ï¡ÁòËáµÎÈëÇâÑõ»¯ÄÆÈÜÒºÖУ¬ÒâÍâ·¢ÏÖÓÐÆøÅݲúÉú£¬ÒÒͬѧÌáÐÑ£ºÊDz»ÊÇÄôíÁËÒ©Æ·£¿µ«¼×ͬѧ²éÑéºóȷʵûÓÐÄôíÒ©Æ·£¬×Ðϸ¹Û²ìÆ¿¿ÚÓа×É«·Ûĩ״ÎïÖÊ£¬¼×»³ÒÉÇâÑõ»¯ÄÆÈÜÒº±äÖÊÁË¡£
£¨1£©ÇâÑõ»¯ÄÆÈÜÒºÔÚ¿ÕÆøÖбäÖʵÄÔ­ÒòÊÇ                        ¡£
£¨2£©ÀûÓÃÓëÉÏÊöʵÑ鲻ͬµÄÔ­Àí£¬¼×ͬѧÉè¼ÆÁËÒ»¸öÑéÖ¤¸ÃÇâÑõ»¯ÄÆÈÜÒºÊDz¿·Ö±äÖÊ»¹ÊÇÈ«²¿±äÖʵÄʵÑ飺
£¨3£©Ð´³öÔÚ²¿·Ö±äÖʵÄÇâÑõ»¯ÄÆÈÜÒºÖеμÓÏ¡ÑÎËá·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                       ¡£
£¨1£©¿ÕÆøÖеĶþÑõ»¯Ì¼ÊôÓÚËáÐÔ»¯ºÏÎïÄÜÓë³Ê¼îÐÔµÄNaOHÈÜÒº·¢Éú·´Ó¦£¨»òÕß2NaOH+CO2===Na2CO3+H2O£©
£¨2£©

£¨3£©NaOH+HCl===NaCl+H2O£»Na2CO3+2HCl===2NaCl+CO2¡ü+H2O
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø