题目内容
(2010?十堰模拟)
计算下列各题 125-25×6÷30 |
(
|
1.8+4.3+0.7+4.2 | ||||
8.3×9.9+8.3×0.1 | 25×16×50×0.13 |
|
分析:①(
+
)×45、8.3×9.9+8.3×0.1两式可据乘法分配律进行简便计算;
②1.8+4.3+0.7+4.2可据加法交换律进行简便计算;
③25×16×50×0.13可变为(25×4)×(4×50)×0.13进行计算;
④其余据四则混合运算法则进行计算即可.
2 |
3 |
2 |
15 |
②1.8+4.3+0.7+4.2可据加法交换律进行简便计算;
③25×16×50×0.13可变为(25×4)×(4×50)×0.13进行计算;
④其余据四则混合运算法则进行计算即可.
解答:解:(1)125-25×6÷30
=125-150÷30,
=125-5,
=120;
(2)(
+
)×45
=
×45+
×45,
=30+6,
=36;
(3)1.8+4.3+0.7+4.2
=(1.8+4.2)+(4.3+0.7),
=6+5,
=11;
(4)8.3×9.9+8.3×0.1
=(9.9+0.1)×8.3,
=10×8.3,
=83;
(5)25×16×50×0.13
=(25×4)×(4×50)×0.13,
=100×200×0.13,
=2600;
(6)
+0.45÷0.9-
=
+0.5-
,
=1-
,
=
.
=125-150÷30,
=125-5,
=120;
(2)(
2 |
3 |
2 |
15 |
=
2 |
3 |
2 |
15 |
=30+6,
=36;
(3)1.8+4.3+0.7+4.2
=(1.8+4.2)+(4.3+0.7),
=6+5,
=11;
(4)8.3×9.9+8.3×0.1
=(9.9+0.1)×8.3,
=10×8.3,
=83;
(5)25×16×50×0.13
=(25×4)×(4×50)×0.13,
=100×200×0.13,
=2600;
(6)
1 |
2 |
5 |
8 |
=
1 |
2 |
5 |
8 |
=1-
5 |
8 |
=
3 |
8 |
点评:完成本题要认真分析各组数据,尽量用简便方法计算.
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