题目内容
16.能简算的要简算.$\frac{10}{11}$×$\frac{1}{13}$×13×11 | $\frac{4}{9}$×$\frac{9}{14}$÷$\frac{4}{21}$ | $\frac{13}{49}$×21+28×$\frac{13}{49}$ | $\frac{3}{4}$-$\frac{4}{5}$×$\frac{5}{6}$ |
($\frac{3}{4}$+$\frac{5}{8}$)×32 | $\frac{1}{5}$+$\frac{2}{9}$×$\frac{3}{10}$ | 72×$\frac{5}{71}$. |
分析 (1)利用乘法交换律与结合律简算;
(2)把除法改为乘法,直接约分计算;
(3)(5)(7)利用乘法分配律简算;
(4)先算乘法,再算减法;
(6)先算乘法,再算加法.
解答 解:(1)$\frac{10}{11}$×$\frac{1}{13}$×13×11
=$\frac{10}{11}$×11×($\frac{1}{13}$×13)
=10;
(2)$\frac{4}{9}$×$\frac{9}{14}$÷$\frac{4}{21}$
=$\frac{4}{9}$×$\frac{9}{14}$×$\frac{21}{4}$
=$\frac{3}{2}$;
(3)$\frac{13}{49}$×21+28×$\frac{13}{49}$
=$\frac{13}{49}$×(21+28)
=$\frac{13}{49}$×49
=13;
(4)$\frac{3}{4}$-$\frac{4}{5}$×$\frac{5}{6}$
=$\frac{3}{4}$-$\frac{2}{3}$
=$\frac{1}{12}$;
(5)($\frac{3}{4}$+$\frac{5}{8}$)×32
=$\frac{3}{4}$×32+$\frac{5}{8}$×32
=24+20
=44;
(6)$\frac{1}{5}$+$\frac{2}{9}$×$\frac{3}{10}$
=$\frac{1}{5}$+$\frac{1}{15}$
=$\frac{4}{15}$;
(7)72×$\frac{5}{71}$
=71×$\frac{5}{71}$+1×$\frac{5}{71}$
=5+$\frac{5}{71}$
=5$\frac{5}{71}$.
点评 分数四则混合运算的关键是抓住运算顺序,正确按运算顺序计算,适当利用运算定律简算.