题目内容
计算.(能简算的要用简便方法计算)
①25×
×
×
;
②
÷
+
×
;
③
×58+0.125×41+12.5%;
④
÷[
×( 1-
)].
①25×
1 |
3 |
2 |
5 |
3 |
10 |
②
7 |
9 |
11 |
5 |
2 |
9 |
5 |
11 |
③
1 |
8 |
④
4 |
5 |
5 |
8 |
1 |
5 |
分析:(1)运用乘法交换律和结合律即可解答,
(2)(3)运用乘法分配律解答,
(4)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序计算即可解答.
(2)(3)运用乘法分配律解答,
(4)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序计算即可解答.
解答:解:(1)25×
×
×
=(25×
)×(
×
)
=10×
=1;
(2)
÷
+
×
=(
+
)×
=1×
=
;
(3)
×58+0.125×41+12.5%
=
×(58+41+1)
=
×100
=12.5;
(4)
÷[
×(1-
)]
=
÷[
×
]
=
÷
=1
.
1 |
3 |
2 |
5 |
3 |
10 |
=(25×
2 |
5 |
1 |
3 |
3 |
10 |
=10×
1 |
10 |
=1;
(2)
7 |
9 |
11 |
5 |
2 |
9 |
5 |
11 |
=(
7 |
9 |
2 |
9 |
5 |
11 |
=1×
5 |
11 |
=
5 |
11 |
(3)
1 |
8 |
=
1 |
8 |
=
1 |
8 |
=12.5;
(4)
4 |
5 |
5 |
8 |
1 |
5 |
=
4 |
5 |
5 |
8 |
4 |
5 |
=
4 |
5 |
1 |
2 |
=1
3 |
5 |
点评:本题考查知识点:(1)运用简便方法正确解决问题,(2)依据四则运算计算方法正确进行计算.
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