题目内容
计算.(能简算的要用简便方法计算)
|
36×(
|
25×
| ||||||||||||||||||||||||
|
[
|
|
分析:(1)化除以
为乘
,再运用乘法交换律即可解答,
(2)(4)运用乘法分配律解答,
(3)运用乘法交换律和结合律即可解答,
(5)(6)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序计算即可解答.
11 |
6 |
6 |
11 |
(2)(4)运用乘法分配律解答,
(3)运用乘法交换律和结合律即可解答,
(5)(6)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序计算即可解答.
解答:解:(1)
×
÷
=
×
×
=
×
=1;
(2)36×(
+
)
=36×
+36×
=27+3
=30;
(3)25×
×
×
=(25×
)×(
×
)
=10×
=1;
(4)
÷
+
×
=(
+
)×
=
×
=
;
(5)[
-(
-
)]÷
=[
-
]÷
=
÷
=
;
(6)
÷[(
-
)÷
]
=
÷[
÷
]
=
÷
=4.
44 |
9 |
3 |
8 |
11 |
6 |
=
44 |
9 |
6 |
11 |
3 |
8 |
=
8 |
3 |
3 |
8 |
=1;
(2)36×(
3 |
4 |
1 |
12 |
=36×
3 |
4 |
1 |
12 |
=27+3
=30;
(3)25×
1 |
3 |
2 |
5 |
3 |
10 |
=(25×
2 |
5 |
1 |
3 |
3 |
10 |
=10×
1 |
10 |
=1;
(4)
2 |
9 |
11 |
5 |
2 |
9 |
5 |
11 |
=(
2 |
9 |
2 |
9 |
5 |
11 |
=
4 |
9 |
5 |
11 |
=
20 |
99 |
(5)[
1 |
2 |
3 |
4 |
3 |
5 |
7 |
10 |
=[
1 |
2 |
3 |
20 |
7 |
10 |
=
7 |
20 |
7 |
10 |
=
1 |
2 |
(6)
4 |
5 |
5 |
8 |
1 |
2 |
5 |
8 |
=
4 |
5 |
1 |
8 |
5 |
8 |
=
4 |
5 |
1 |
5 |
=4.
点评:本题主要考查学生依据四则运算计算方法,以及运用简便方法解决问题的能力.
练习册系列答案
相关题目