题目内容

脱式计算.
2004×8.1+1.9×2004
1
5
-(
3
5
+
3
5
×
1
3
)×
1
4
(1-
3
4
)÷(
3
10
+
1
5
4.38×0.75+3.62×0.75 12
1
2
×11-12.5
35÷[(
5
6
-
2
3
)×3].
分析:(1)(4)(5)可根据乘法分配律计算;
(2)(3)(6)根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
解答:解:(1)2004×8.1+1.9×2004
=(8.1+1.9)×2004,
=10×2004,
=20040;

(2)
1
5
-(
3
5
+
3
5
×
1
3
)×
1
4

=
1
5
-(
3
5
+
1
5
)×
1
4

=
1
5
-
4
5
×
1
4

=
1
5
-
1
5

=0;

(3)(1-
3
4
)÷(
3
10
+
1
5

=
1
4
÷
1
2

=
1
2


(4)4.38×0.75+3.62×0.75
=(4.38+3.62)×0.75,
=8×0.75,
=6;

(5)12
1
2
×11-12.5
=12.5×11-12.5,
=(11-1)×12.5,
=10×12.5,
=125;

(6)35÷[(
5
6
-
2
3
)×3].
=35÷[
1
3
×3],
=35÷1,
=35.
点评:完成脱式计算时要注意计算过程的完整性,中间不要有太大跳跃.
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