题目内容
脱式计算. 2004×8.1+1.9×2004 | -(+×)× | (1-)÷(+) |
4.38×0.75+3.62×0.75 | 12×11-12.5 | 35÷[(-)×3]. |
解:(1)2004×8.1+1.9×2004
=(8.1+1.9)×2004,
=10×2004,
=20040;
(2)-(+×)×
=-(+)×,
=-×,
=,
=0;
(3)(1-)÷(+)
=÷,
=;
(4)4.38×0.75+3.62×0.75
=(4.38+3.62)×0.75,
=8×0.75,
=6;
(5)12×11-12.5
=12.5×11-12.5,
=(11-1)×12.5,
=10×12.5,
=125;
(6)35÷[(-)×3].
=35÷[×3],
=35÷1,
=35.
分析:(1)(4)(5)可根据乘法分配律计算;
(2)(3)(6)根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
点评:完成脱式计算时要注意计算过程的完整性,中间不要有太大跳跃.
=(8.1+1.9)×2004,
=10×2004,
=20040;
(2)-(+×)×
=-(+)×,
=-×,
=,
=0;
(3)(1-)÷(+)
=÷,
=;
(4)4.38×0.75+3.62×0.75
=(4.38+3.62)×0.75,
=8×0.75,
=6;
(5)12×11-12.5
=12.5×11-12.5,
=(11-1)×12.5,
=10×12.5,
=125;
(6)35÷[(-)×3].
=35÷[×3],
=35÷1,
=35.
分析:(1)(4)(5)可根据乘法分配律计算;
(2)(3)(6)根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
点评:完成脱式计算时要注意计算过程的完整性,中间不要有太大跳跃.
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