题目内容
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分析:先找到所有小于平角的角相加为∠AOC+∠BOC+∠AOB+∠AOD+∠BOD=(∠AOC+∠AOD)+(∠BOC+∠BOD)+∠AOB=400,再根据平角=180°,即可求出∠AOB.
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解答:解:∠AOC+∠BOC+∠AOB+∠AOD+∠BOD
=(∠AOC+∠AOD)+(∠BOC+∠BOD)+∠AOB
=360°+∠AOB
=400,
则∠AOB=400°-360=40°.
故答案为:40.
=(∠AOC+∠AOD)+(∠BOC+∠BOD)+∠AOB
=360°+∠AOB
=400,
则∠AOB=400°-360=40°.
故答案为:40.
点评:考查了角的计数和平角的定义,得到∠AOC+∠BOC+∠AOB+∠AOD+∠BOD=(∠AOC+∠AOD)+(∠BOC+∠BOD)+∠AOB=360°+∠AOB是解题的关键.
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