题目内容
(2012?武汉模拟)(1)(5.77×4
+3
×5
)×(3
-1÷
)
(2)[(1
×2+2.5)÷
-2
]÷1.6
(3)(
+
)×2.5÷(4
×
+6
÷8
×1
)
(4)8
÷[(7.35-5
)÷1.02]+79.5×
.
2 |
7 |
2 |
7 |
7 |
10 |
2 |
7 |
7 |
23 |
(2)[(1
2 |
3 |
7 |
8 |
1 |
5 |
(3)(
1 |
12.5 |
1 |
10 |
11 |
16 |
4 |
25 |
11 |
14 |
1 |
7 |
1 |
2 |
(4)8
8 |
9 |
1 |
12 |
4 |
35 |
分析:(1)两个括号内的同时计算,第一个括号先算乘法,再算加法;第二个括号先算除法,再算减法;最后算括号外的乘法;
(2)先算小括号内的乘法,在算小括号内的加法,然后算中括号的除法和减法,最后算括号外的除法;
(3)先算括号内的,第二个括号先算乘除,再算加法,然后从左往右依次计算;
(4)先算小括号内的,再算中括号内的,然后算括号外的乘除,最后算加法.
(2)先算小括号内的乘法,在算小括号内的加法,然后算中括号的除法和减法,最后算括号外的除法;
(3)先算括号内的,第二个括号先算乘除,再算加法,然后从左往右依次计算;
(4)先算小括号内的,再算中括号内的,然后算括号外的乘除,最后算加法.
解答:解:(1)(5.77×4
+3
×5
)×(3
-1÷
)
=(5.77×4
+3
×5
)×(
-
)
=(5.77×4
+3
×5
)×0
=0;
(2)[(1
×2+2.5)÷
-2
]÷1.6
=[(
×2+
)÷
-2
]÷1.6
=[
÷
-2
]÷1.6
=[
×
-2
]÷1.6
=[
-
]÷
=
×
=
;
(3)(
+
)×2.5÷(4
×
+6
÷8
×1
)
=(
+
)×2.5÷(
×
+
×
×
)
=
×
÷(
+
)
=
÷2
=
×
=
;
(4)8
÷[(7.35-5
)÷1.02]+79.5×
=8
÷[(7
-5
)÷
]+
×
=8
÷[
×
]+
=8
÷
+
=
×
+
=4+9
=13
.
2 |
7 |
2 |
7 |
7 |
10 |
2 |
7 |
7 |
23 |
=(5.77×4
2 |
7 |
2 |
7 |
7 |
10 |
23 |
7 |
23 |
7 |
=(5.77×4
2 |
7 |
2 |
7 |
7 |
10 |
=0;
(2)[(1
2 |
3 |
7 |
8 |
1 |
5 |
=[(
5 |
3 |
5 |
2 |
7 |
8 |
1 |
5 |
=[
35 |
6 |
7 |
8 |
1 |
5 |
=[
35 |
6 |
8 |
7 |
1 |
5 |
=[
20 |
3 |
11 |
5 |
8 |
5 |
=
67 |
15 |
5 |
8 |
=
67 |
24 |
(3)(
1 |
12.5 |
1 |
10 |
11 |
16 |
4 |
25 |
11 |
14 |
1 |
7 |
1 |
2 |
=(
2 |
25 |
1 |
10 |
75 |
16 |
4 |
25 |
95 |
14 |
7 |
57 |
3 |
2 |
=
9 |
50 |
5 |
2 |
3 |
4 |
5 |
4 |
=
9 |
20 |
=
9 |
20 |
1 |
2 |
=
9 |
40 |
(4)8
8 |
9 |
1 |
12 |
4 |
35 |
=8
8 |
9 |
7 |
20 |
1 |
12 |
51 |
50 |
158 |
2 |
4 |
35 |
=8
8 |
9 |
34 |
15 |
50 |
51 |
316 |
35 |
=8
8 |
9 |
20 |
9 |
316 |
35 |
=
80 |
9 |
9 |
20 |
316 |
35 |
=4+9
1 |
35 |
=13
1 |
35 |
点评:此题考查了分数的四则混合运算,注意运算顺序和运算法则.
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