题目内容
递等式计算.
743-450÷18×25 | 88×
| ||||
519.2÷(24.3×2-4.6) | 126×98+126+63×2. |
分析:(1)(2)(3)依据四则混合运算的计算顺序,先算第二级运算,再算第一级运算,如果只含有同一级运算,按照从左到右顺序计算,有括号先算括号里面的解答,
(4)先求出63乘2的积,再运用乘法分配律解答.
(4)先求出63乘2的积,再运用乘法分配律解答.
解答:解:(1)743-450÷18×25,
=743-25×25,
=743-625,
=118;
(2)88×
×(1÷
-1),
=88×
×(
-1),
=88×
×
,
=
×
,
=19
;
(3)519.2÷(24.3×2-4.6),
=519.2÷(48.6-4.6),
=519.2÷44,
=11.8;
(4)126×98+126+63×2,
=126×98+126+126,
=126×(98+1+1),
=126×100,
=12600.
=743-25×25,
=743-625,
=118;
(2)88×
2 |
3 |
3 |
4 |
=88×
2 |
3 |
4 |
3 |
=88×
2 |
3 |
1 |
3 |
=
176 |
3 |
1 |
3 |
=19
5 |
9 |
(3)519.2÷(24.3×2-4.6),
=519.2÷(48.6-4.6),
=519.2÷44,
=11.8;
(4)126×98+126+63×2,
=126×98+126+126,
=126×(98+1+1),
=126×100,
=12600.
点评:本题主要考查学生依据四则混合运算的顺序,以及正确运用乘法分配律解决问题的能力,注意计算的准确性.
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