题目内容
递等式计算
(2-
)÷
-
94.2÷[3.6×(
-
)]
2630-630÷21.
(2-
6 |
13 |
9 |
26 |
2 |
3 |
94.2÷[3.6×(
1 |
3 |
1 |
4 |
2630-630÷21.
分析:(1)先通分计算小括号内部的在计算括号外面的使计算更加简便.
(2)中括号内部的计算运用乘法的分配律进行计算然后再计算括号外面的,这样计算会更加简便.
(3)按照先做除法再做减法运算顺序进行计算,可得正确答案.
(2)中括号内部的计算运用乘法的分配律进行计算然后再计算括号外面的,这样计算会更加简便.
(3)按照先做除法再做减法运算顺序进行计算,可得正确答案.
解答:解:(1)(2-
)÷
-
,
=(
-
)×
-
,
=
×
-
,
=
-
,
=
,
=3
;
(2)94.2÷[3.6×(
-
)],
=94.2÷[3.6×
-3.6×
],
=94.2÷[1.2-0.9],
=94.2÷0.3,
=314;
(3)2630-630÷21,
=2630-30,
=2600;
6 |
13 |
9 |
26 |
2 |
3 |
=(
26 |
13 |
6 |
13 |
26 |
9 |
2 |
3 |
=
20 |
13 |
26 |
9 |
2 |
3 |
=
40 |
9 |
6 |
9 |
=
34 |
9 |
=3
7 |
9 |
(2)94.2÷[3.6×(
1 |
3 |
1 |
4 |
=94.2÷[3.6×
1 |
3 |
1 |
4 |
=94.2÷[1.2-0.9],
=94.2÷0.3,
=314;
(3)2630-630÷21,
=2630-30,
=2600;
点评:本题考查了四则混合的运算顺序及运算定律的灵活运用.
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