题目内容
用递等式计算
6÷
|
(1000-0.16×1900)÷96 |
| |||||||||||||
(
|
|
(1)6÷
-
÷6,
=10-
,
=9
;
(2)(1000-0.16×1900)÷96,
=÷96,
=696÷96,
=7.25;
(3)
×[
÷(
-
)],
=
×[
÷
],
=
×
,
=4;
(4)(
+
)÷(
-
),
=
÷
,
=
;
(5)
×[1÷(
+
)],
=
×[1÷
],
=
×
,
=
.
3 |
5 |
3 |
5 |
=10-
1 |
10 |
=9
9 |
10 |
(2)(1000-0.16×1900)÷96,
=÷96,
=696÷96,
=7.25;
(3)
3 |
8 |
8 |
9 |
5 |
6 |
3 |
4 |
=
3 |
8 |
8 |
9 |
1 |
12 |
=
3 |
8 |
32 |
3 |
=4;
(4)(
5 |
8 |
1 |
4 |
2 |
3 |
1 |
2 |
=
7 |
8 |
1 |
6 |
=
21 |
4 |
(5)
5 |
8 |
3 |
4 |
1 |
3 |
=
5 |
8 |
13 |
12 |
=
5 |
8 |
12 |
13 |
=
15 |
26 |
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