题目内容
用递等式计算.(能简算的就简算)
(1)2.54×9+1.27×(0.5÷O.25)
(2)12÷(4.32-4.O2)×O.47.
(1)2.54×9+1.27×(0.5÷O.25)
(2)12÷(4.32-4.O2)×O.47.
分析:(1)小数小括号里面的除法,再算1.27×2=2.5,然后再根据乘法分配律进行简算;
(2)先算减法,再算除法,最后算乘法.
(2)先算减法,再算除法,最后算乘法.
解答:解:(1)2.54×9+1.27×(0.5÷O.25),
=2.54×9+1.27×2,
=2.54×9+2.54,
=2.54×(9+1),
=2.54×10,
=25.4;
(2)12÷(4.32-4.O2)×O.47,
=12÷0.3×O.47,
=40×O.47,
=18.8.
=2.54×9+1.27×2,
=2.54×9+2.54,
=2.54×(9+1),
=2.54×10,
=25.4;
(2)12÷(4.32-4.O2)×O.47,
=12÷0.3×O.47,
=40×O.47,
=18.8.
点评:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
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