题目内容
用递等式计算.
(1)0.6÷0.125÷0.8 | (2)(100-6.4)÷3.6+5.4 |
(3)3.9÷(1.3×5) | (4)5.04×3.6+50.4×0.64. |
分析:(1)运用除法的性质简算;
(2)先算括号内的,再算括号外的除法,最后算加法;
(3)先算括号内的,再算括号外的;
(4)根据数字特点,原式变为5.04×3.6+5.04×6.4,运用乘法分配律简算.
(2)先算括号内的,再算括号外的除法,最后算加法;
(3)先算括号内的,再算括号外的;
(4)根据数字特点,原式变为5.04×3.6+5.04×6.4,运用乘法分配律简算.
解答:解:(1)0.6÷0.125÷0.8,
=0.6÷(0.125×0.8),
=0.6÷0.1,
=6;
(2)(100-6.4)÷3.6+5.4,
=93.6÷3.6+5.4,
=26+5.4,
=31.4;
(3)3.9÷(1.3×5),
=3.9÷6.5,
=0.6;
(4)5.04×3.6+50.4×0.64,
=5.04×3.6+5.04×6.4,
=5.04×(3.6+6.4),
=5.04×10,
=50.4.
=0.6÷(0.125×0.8),
=0.6÷0.1,
=6;
(2)(100-6.4)÷3.6+5.4,
=93.6÷3.6+5.4,
=26+5.4,
=31.4;
(3)3.9÷(1.3×5),
=3.9÷6.5,
=0.6;
(4)5.04×3.6+50.4×0.64,
=5.04×3.6+5.04×6.4,
=5.04×(3.6+6.4),
=5.04×10,
=50.4.
点评:此题考查了小数的四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
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