题目内容
解方程.
(1)4x+2(8-x)=36
(2)
x=
×
.
解:(1)4x+2(8-x)=36,
4x+16-2x=36,
2x+16=36,
2x+16-16=36-16,
2x=20,
2x÷2=20÷2,
x=10;
(2)
x=
×
,
x÷
=
×
÷
,
x=
×
×
,
x=
.
分析:(1)根据题意,先计算2(8-x)=16-2x,再计算4x-2x=2x,等式的两边同时减去16,然后等式的两边再同时除以2即可;
(2)等式的两边同时除以
即可.
点评:本题主要考查解方程,根据等式的性质进行解答即可.
4x+16-2x=36,
2x+16=36,
2x+16-16=36-16,
2x=20,
2x÷2=20÷2,
x=10;
(2)
![](http://thumb.1010pic.com/pic5/latex/729.png)
![](http://thumb.1010pic.com/pic5/latex/7.png)
![](http://thumb.1010pic.com/pic5/latex/176475.png)
![](http://thumb.1010pic.com/pic5/latex/729.png)
![](http://thumb.1010pic.com/pic5/latex/729.png)
![](http://thumb.1010pic.com/pic5/latex/7.png)
![](http://thumb.1010pic.com/pic5/latex/176475.png)
![](http://thumb.1010pic.com/pic5/latex/729.png)
x=
![](http://thumb.1010pic.com/pic5/latex/7.png)
![](http://thumb.1010pic.com/pic5/latex/176475.png)
![](http://thumb.1010pic.com/pic5/latex/4491.png)
x=
![](http://thumb.1010pic.com/pic5/latex/7128.png)
分析:(1)根据题意,先计算2(8-x)=16-2x,再计算4x-2x=2x,等式的两边同时减去16,然后等式的两边再同时除以2即可;
(2)等式的两边同时除以
![](http://thumb.1010pic.com/pic5/latex/729.png)
点评:本题主要考查解方程,根据等式的性质进行解答即可.
![](http://thumb2018.1010pic.com/images/loading.gif)
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