题目内容
求未知数x的值
(1)
x-
x=4.9
(2)0.36×5-
x=
(3)
:0.8=x:48.
(1)
2 |
3 |
1 |
5 |
(2)0.36×5-
3 |
4 |
3 |
5 |
(3)
1 |
6 |
分析:(1)运用乘法分配律改写成(
-
)x=4.9,即
x=4.9,根据等式的性质,两边同乘
即可;
(2)先求出0.36×5=1.8,原式变为1.8-
x=
,根据等式的性质,两边同加上
x,得0.6+
x=1.8,两边同减去0.6,再同乘
即可;
(3)先根据比例的性质改写成0.8x=
×48,再根据等式的性质,两边同除以0.8即可.
2 |
3 |
1 |
5 |
7 |
15 |
15 |
7 |
(2)先求出0.36×5=1.8,原式变为1.8-
3 |
4 |
3 |
5 |
3 |
4 |
3 |
4 |
4 |
3 |
(3)先根据比例的性质改写成0.8x=
1 |
6 |
解答:解:(1)
x-
x=4.9,
(
-
)x=4.9,
x=4.9,
x×
=4.9×
,
x=10.5;
(2)0.36×5-
x=
,
1.8-
x=
,
1.8-
x+
x=
+
x,
0.6+
x=1.8,
0.6+
x-0.6=1.8-0.6,
x=1.2,
x×
=1.2×
,
x=1.6;
(3)
:0.8=x:48,
0.8x=
×48,
0.8x÷0.8=8÷0.8,
x=10.
2 |
3 |
1 |
5 |
(
2 |
3 |
1 |
5 |
7 |
15 |
7 |
15 |
15 |
7 |
15 |
7 |
x=10.5;
(2)0.36×5-
3 |
4 |
3 |
5 |
1.8-
3 |
4 |
3 |
5 |
1.8-
3 |
4 |
3 |
4 |
3 |
5 |
3 |
4 |
0.6+
3 |
4 |
0.6+
3 |
4 |
3 |
4 |
3 |
4 |
4 |
3 |
4 |
3 |
x=1.6;
(3)
1 |
6 |
0.8x=
1 |
6 |
0.8x÷0.8=8÷0.8,
x=10.
点评:此题考查了根据等式的性质解方程,即等式两边同加、同减、同乘或同除以一个数(0除外),等式的左右两边仍相等;注意等号上下要对齐.
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