题目内容
求未知数x的值
(1)
=
:
(2)x-
x=
(3)
X-21×
=4.
(1)
x |
21 |
4 |
9 |
1 |
6 |
(2)x-
1 |
4 |
3 |
8 |
(3)
3 |
10 |
2 |
3 |
分析:(1)根据比与除法的关系,
:
化成
÷
,然后等式的两边再同时乘21即可;
(2)先计算,x-
x=
x,然后等式的两边同时除以
即可;
(3)先计算21×
=14,等式的两边同时加14,然后等式的两边同时除以
即可.
4 |
9 |
1 |
6 |
4 |
9 |
1 |
6 |
(2)先计算,x-
1 |
4 |
3 |
4 |
3 |
4 |
(3)先计算21×
2 |
3 |
3 |
10 |
解答:解:(1)
=
:
,
=
÷
,
×21=
÷
×21,
x=
×6×21,
x=56;
(2)x-
x=
,
x=
,
x÷
=
÷
,
x=
;
(3)
X-21×
=4,
X-14=4,
X-14+14=4+14,
X=18,
X÷
=18÷
,
X=60.
x |
21 |
4 |
9 |
1 |
6 |
x |
21 |
4 |
9 |
1 |
6 |
x |
21 |
4 |
9 |
1 |
6 |
x=
4 |
9 |
x=56;
(2)x-
1 |
4 |
3 |
8 |
3 |
4 |
3 |
8 |
3 |
4 |
3 |
4 |
3 |
8 |
3 |
4 |
x=
1 |
2 |
(3)
3 |
10 |
2 |
3 |
3 |
10 |
3 |
10 |
3 |
10 |
3 |
10 |
3 |
10 |
3 |
10 |
X=60.
点评:本题主要考查解方程,根据等式的性质进行解答即可.
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