题目内容

递等式计算
1÷(
1
2
÷
1
3
)
3
8
-
3
10
×
5
6
3
13
×8÷
10
13
×8
3
10
×(
5
7
-
10
21
)
9
10
÷
7
22
×
14
33
3
8
+
5
8
÷
15
16
分析:(1)(4)先算括号内的,再算括号外的;
(2)先算乘法,再算减法;
(3)把除法改为乘法,运用乘法交换律与结合律简算;
(5)把除法改为乘法,约分计算;
(6)先算除法,再算加法.
解答:解:(1)1÷(
1
2
÷
1
3
),
=1÷(
1
2
×3),
=1÷
3
2

=
2
3


(2)
3
8
-
3
10
×
5
6

=
3
8
-
1
4

=
1
8


(3)
3
13
×8÷
10
13
×8,
=
3
13
×8×
13
10
×8,
=(
3
13
×
13
10
)×(8×8),
=
3
10
×64,
=
96
5


(4)
3
10
×(
5
7
-
10
21
),
=
3
10
×
5
21

=
1
14


(5)
9
10
÷
7
22
×
14
33

=
9
10
×
22
7
×
14
33

=
6
5


(6)
3
8
+
5
8
÷
15
16

=
3
8
+
5
8
×
16
15

=
3
8
+
2
3

=
25
24
点评:考查了分数的四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律简便计算.
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