题目内容
用递等式计算(能简算的就用简便方法计算)
3.72×3.5+3.5×6.28
0.25×16.2×4
.
解:(1)3.72×3.5+3.5×6.28,
=3.5×(3.72+6.28),
=3.5×10,
=35;
(2)0.25×16.2×4,
=0.25×4×16.2,
=1×16.2,
=16.2;
(3)(),
=×36-×36,
=4-3,
=1;
(4)÷4,
=+÷4,
=+,
=.
分析:(1)(3)运用乘法分配律(1)化原式=3.5×(3.72+6.28),(3)化原式=×36×36解答,
(2)运用乘法交换律化原式=0.25×4×16.2解答,
(4)依据四则运算计算方法解答.
点评:本题主要考查学生对于乘法交换律,以及乘法分配律的灵活运用.
=3.5×(3.72+6.28),
=3.5×10,
=35;
(2)0.25×16.2×4,
=0.25×4×16.2,
=1×16.2,
=16.2;
(3)(),
=×36-×36,
=4-3,
=1;
(4)÷4,
=+÷4,
=+,
=.
分析:(1)(3)运用乘法分配律(1)化原式=3.5×(3.72+6.28),(3)化原式=×36×36解答,
(2)运用乘法交换律化原式=0.25×4×16.2解答,
(4)依据四则运算计算方法解答.
点评:本题主要考查学生对于乘法交换律,以及乘法分配律的灵活运用.
练习册系列答案
相关题目