题目内容
用递等式计算(能简算得就要简算)
|
(
|
6.5×6+3.5×6-35 | ||||||||||||||||||||
1
|
0.35÷[(
|
|
分析:(1)运用乘法的分配律进行简算,
(2)把÷
化成乘以7,再算小括号里的
+
,最后运用乘法的分配律进行简算,
(3)运用乘法的分配律进行简算,最后算减法,
(4)运用乘法的分配律进行简算,
(5)先算小括号里的 减法,再算中括号里的乘法,最后算除法,
(6)先算小括号里的加法,再从左向右算除法,最后算减法.
(2)把÷
1 |
7 |
1 |
4 |
3 |
4 |
(3)运用乘法的分配律进行简算,最后算减法,
(4)运用乘法的分配律进行简算,
(5)先算小括号里的 减法,再算中括号里的乘法,最后算除法,
(6)先算小括号里的加法,再从左向右算除法,最后算减法.
解答:解:(1)
×
+
×
,
=(
+
)×
,
=1×
,
=
;
(2)(
+
+
)÷
,
=(
+
+
)×7,
=(1+
)×7,
=1×7+
×7+,
=7+
,
=9
;
(3)6.5×6+3.5×6-35,
=(6.5+3.5)×6-35,
=10×6-35,
=60-35,
=25;
(4)1
×
+
×0.125-
,
=(1
+0.125-1)×
,
=(2-1)×
,
=1×
,
=
;
(5)0.35÷[(
-
)×3],
=0.35÷[
×3],
=0.35÷
,
=0.7,
(6)
÷(
+
)÷
-10,
=
÷
÷
-10,
=
÷
-10,
=10-10,
=0.
3 |
4 |
2 |
5 |
3 |
5 |
3 |
4 |
=(
2 |
5 |
3 |
5 |
3 |
4 |
=1×
3 |
4 |
=
3 |
4 |
(2)(
1 |
4 |
5 |
14 |
3 |
4 |
1 |
7 |
=(
1 |
4 |
3 |
4 |
5 |
14 |
=(1+
5 |
14 |
=1×7+
5 |
14 |
=7+
5 |
2 |
=9
1 |
2 |
(3)6.5×6+3.5×6-35,
=(6.5+3.5)×6-35,
=10×6-35,
=60-35,
=25;
(4)1
7 |
8 |
5 |
9 |
5 |
9 |
5 |
9 |
=(1
7 |
8 |
5 |
9 |
=(2-1)×
5 |
9 |
=1×
5 |
9 |
=
5 |
9 |
(5)0.35÷[(
5 |
6 |
2 |
3 |
=0.35÷[
1 |
6 |
=0.35÷
1 |
2 |
=0.7,
(6)
2 |
3 |
2 |
3 |
1 |
5 |
1 |
13 |
=
2 |
3 |
13 |
15 |
1 |
13 |
=
10 |
13 |
1 |
13 |
=10-10,
=0.
点评:此题考查了分数、小数四则混合运算的顺序,要灵活运用运算定律进行简算.
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