题目内容
(2010?南丹县模拟)
灵活计算下面各题. (1)9315÷23+77 |
(2)7.38-(1.57+2.38) | ||||||||||||
(3)
|
(4)
|
分析:(1)先算9315÷23,再算商加上77;
(2)利用一个数减去两个数的和等于一个数连续减去两个数变成7.38-1.57-2.38,再利用减法的交换律变成7.38-2.38-1.57计算简便;
(3)利用乘法的分配律变成
×(99+1)计算简便;
(4)按四则运算的顺序
(2)利用一个数减去两个数的和等于一个数连续减去两个数变成7.38-1.57-2.38,再利用减法的交换律变成7.38-2.38-1.57计算简便;
(3)利用乘法的分配律变成
9 |
19 |
(4)按四则运算的顺序
解答:解:(1)9315÷23+77,
=405+77,
=482;
(2)7.38-(1.57+2.38),
=7.38-1.57-2.38,
=7.38-2.38-1.57,
=5-1.57,
=3.43;
(3)
+
×99,
=
×(99+1),
=
×100,
=90;
(4)
÷[(
+
)÷
],
=
÷[
×
],
=
÷
,
=
.
=405+77,
=482;
(2)7.38-(1.57+2.38),
=7.38-1.57-2.38,
=7.38-2.38-1.57,
=5-1.57,
=3.43;
(3)
9 |
10 |
9 |
10 |
=
9 |
10 |
=
9 |
10 |
=90;
(4)
3 |
5 |
1 |
5 |
1 |
3 |
2 |
9 |
=
3 |
5 |
8 |
15 |
9 |
2 |
=
3 |
5 |
12 |
5 |
=
1 |
4 |
点评:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
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