题目内容
(2012?莲都区模拟)(1)
x+
=
(2)X:8=
:1
(3)85×0.75+4785÷15
(4)4×17×125×
÷
(5)
÷〔
÷2
×(4.3-1.8)〕÷26
(6)〔1-(
+
)〕÷
(7)n!表示从1到n的n个连续自然数的乘积,例如 10!=10×9×8×…×2×1请计算:1!+4!+5!
3 |
4 |
1 |
8 |
1 |
2 |
(2)X:8=
1 |
4 |
3 |
4 |
(3)85×0.75+4785÷15
(4)4×17×125×
3 |
24 |
1 |
2 |
(5)
1 |
3 |
11 |
52 |
3 |
4 |
(6)〔1-(
1 |
2 |
1 |
6 |
1 |
3 |
(7)n!表示从1到n的n个连续自然数的乘积,例如 10!=10×9×8×…×2×1请计算:1!+4!+5!
分析:(1)根据等式的性质,两边同减去
,再同乘
即可;
(2)先根据比例的性质改写成1
X=8×
,再根据等式的性质,两边同乘
即可;
(3)按运算顺序计算,先算乘法和除法,再算加法;
(4)把除法改为乘法,运用乘法交换律与结合律简算;
(5)先算小括号内的减法,原式变为
÷[
×
×2.5]÷26,再算出中括号内的结果,然后把除法改为乘法,依次计算即可;
(6)先算小括号内的,再算中括号内的,最后算括号外的;
(7)根据特例,列出算式,计算即可.
1 |
8 |
4 |
3 |
(2)先根据比例的性质改写成1
3 |
4 |
1 |
4 |
4 |
7 |
(3)按运算顺序计算,先算乘法和除法,再算加法;
(4)把除法改为乘法,运用乘法交换律与结合律简算;
(5)先算小括号内的减法,原式变为
1 |
3 |
11 |
52 |
4 |
11 |
(6)先算小括号内的,再算中括号内的,最后算括号外的;
(7)根据特例,列出算式,计算即可.
解答:解:(1)
x+
=
,
x+
-
=
-
,
x=
,
x×
=
×
,
x=
;
(2)X:8=
:1
,
1
X=8×
,
X=2,
X×
=2×
,
X=
;
(3)85×0.75+4785÷15,
=63.75+319,
=382.75;
(4)4×17×125×
÷
,
=4×17×125×
×2,
=2125;
(5)
÷〔
÷2
×(4.3-1.8)〕÷26,
=
÷[
×
×2.5]÷26,
=
÷[
×
]÷26,
=
÷
÷26,
=
×
×
,
=
;
(6)〔1-(
+
)〕÷
,
=[1-
]×3,
=
×3,
=1;
(7)1!+4!+5!,
=1+1×2×3×4+1×2×3×4×5,
=1+24+120,
=145.
3 |
4 |
1 |
8 |
1 |
2 |
3 |
4 |
1 |
8 |
1 |
8 |
1 |
2 |
1 |
8 |
3 |
4 |
3 |
8 |
3 |
4 |
4 |
3 |
3 |
8 |
4 |
3 |
x=
1 |
2 |
(2)X:8=
1 |
4 |
3 |
4 |
1
3 |
4 |
1 |
4 |
7 |
4 |
7 |
4 |
4 |
7 |
4 |
7 |
X=
8 |
7 |
(3)85×0.75+4785÷15,
=63.75+319,
=382.75;
(4)4×17×125×
3 |
24 |
1 |
2 |
=4×17×125×
1 |
8 |
=2125;
(5)
1 |
3 |
11 |
52 |
3 |
4 |
=
1 |
3 |
11 |
52 |
4 |
11 |
=
1 |
3 |
1 |
13 |
5 |
2 |
=
1 |
3 |
5 |
26 |
=
1 |
3 |
26 |
5 |
1 |
26 |
=
1 |
15 |
(6)〔1-(
1 |
2 |
1 |
6 |
1 |
3 |
=[1-
2 |
3 |
=
1 |
3 |
=1;
(7)1!+4!+5!,
=1+1×2×3×4+1×2×3×4×5,
=1+24+120,
=145.
点评:此题考查了解方程以及四则混合运算,解方程时运用等式的性质,在做四则混合运算题时,注意运算顺序与运算技巧.
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