题目内容
递等式计算.
(3.12+0.9)÷[(1-0.4)÷0.1] | (4.7+3
|
分析:(1)先算小括号,再算中括号除法,最后算括号外的除法;
(2)先算小括号,再算中括号的乘法,最后算括号外的除法.
(2)先算小括号,再算中括号的乘法,最后算括号外的除法.
解答:解:(1)(3.12+0.9)÷[(1-0.4)÷0.1],
=4.02÷[0.6÷0.1],
=4.02÷6,
=0.67;
(2)(4.7+3
)÷[(4
-3.5)×2
],
=8.1÷[(
×2
],
=8.1÷
,
=5.4.
=4.02÷[0.6÷0.1],
=4.02÷6,
=0.67;
(2)(4.7+3
2 |
5 |
1 |
7 |
1 |
3 |
=8.1÷[(
9 |
14 |
1 |
3 |
=8.1÷
3 |
2 |
=5.4.
点评:考查了小数、分数四则混合运算的顺序及小数分数的互化.
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