题目内容
递等式计算
522-322÷7
(700-621)×68
876+981÷9.
522-322÷7
(700-621)×68
876+981÷9.
分析:本题根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
解答:解:522-322÷7
=522-46,
=476;
(700-621)×68
=79×68,
=5372;
876+981÷9
=876+109,
=985.
=522-46,
=476;
(700-621)×68
=79×68,
=5372;
876+981÷9
=876+109,
=985.
点评:在完成用递等式计算的题目时,要注意计算过程的完整性,中间不要有太大跳跃.
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