题目内容
递等式计算
(12.8+13.2)÷5 | 840÷4×6 | 300-15×12 |
130+12×27 | 58×21-58 | (67-25)×18. |
分析:(1)先算小括号里面的加法,再算括号外的除法;
(2)按照从左到右的顺序计算;
(3)先算乘法,再算减法;
(4)先算乘法,再算加法;
(5)先算乘法,再算减法;
(6)先算小括号里面的减法,再算括号外的乘法.
(2)按照从左到右的顺序计算;
(3)先算乘法,再算减法;
(4)先算乘法,再算加法;
(5)先算乘法,再算减法;
(6)先算小括号里面的减法,再算括号外的乘法.
解答:解:(1)(12.8+13.2)÷5,
=26÷5,
=5.2;
(2)840÷4×6,
=210×6,
=1260;
(3)300-15×12,
=300-180,
=120;
(4)130+12×27,
=130+324,
=454;
(5)58×21-58,
=58×(21-1),
=58×20,
=1160;
(6)(67-25)×18,
=42×18,
=756.
=26÷5,
=5.2;
(2)840÷4×6,
=210×6,
=1260;
(3)300-15×12,
=300-180,
=120;
(4)130+12×27,
=130+324,
=454;
(5)58×21-58,
=58×(21-1),
=58×20,
=1160;
(6)(67-25)×18,
=42×18,
=756.
点评:本题考查了简单的四则混合运算,关键是理清楚运算的顺序,然后根据运算顺序逐步求解即可.
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