题目内容

请你算一算
(1)(3
5
6
+4
5
9
-1
1
4
)÷(1-
35
36
)

(2)999.8×98+(
4
5
-0.6)×9998
(3)[(3
1
5
-3
1
6
)×1.5+2.45]×(1.9-
9
10
)

(4)解方程:(0.5Χ+4
1
2
):
7
10
=Χ:0.6
分析:(1)、(2)运用乘法的分配律进行计算即可.
(3)我们按照四则混合运算的剩下进行计算,先计算中括号内部的小括号,再就是中括号内部的,最后计算中括号外面的.
(4)我们运用比例的基本性质进行解答即可.
解答:解:(1)(3
5
6
+4
5
9
-1
1
4
)÷(1-
35
36
),
=[6+(
5
6
+
5
9
-
1
4
)]×36,
=6×36+(
5
6
+
5
9
-
1
4
)×36,
=36×6+36×
5
6
+36×
5
9
-36×
1
4

=216+30+20-9,
=257;

(2)999.8×98+(
4
5
-0.6)×9998,
=999.8×98+0.2×9998,
=999.8×98+2×999.8,
=999.8×(98+2),
=999.8×100,
=99980;

(3)[(3
1
5
-3
1
6
)×1.5+2.45]×(1.9-
9
10
),
=[
1
30
×1.5+2.45]×1,
=[0.05+2.45]×1,
=2.5;

(4)(0.5x+4
1
2
):
7
10
=x:0.6,
                 0.7x=0.6×(0.5x+4.5)
                 0.7x=0.3x+2.7,
            0.7x-0.3x=0.3x-0.3x+2.7,
                  0.4x=2.7,
            0.4x÷0.4=2.7÷0.4,
                    x=6.75.
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.同时考查了比例基本性质的掌握与运用情况.
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