题目内容
用递等式计算.(怎样简算怎样算)
(1)
×
+
×
(2)
÷5+
×
(3)(
+
)×28
(4)[1-(
+
)]÷
.
(1)
5 |
4 |
5 |
2 |
5 |
4 |
3 |
2 |
(2)
1 |
3 |
2 |
3 |
1 |
5 |
(3)(
4 |
7 |
1 |
2 |
(4)[1-(
3 |
7 |
5 |
14 |
1 |
7 |
分析:第(1)题,运用乘法分配律的逆运算简算;
第(2)题,把除以5改成乘
,然后用乘法分配律的逆运算简算;
第(3)题,运用乘法分配律简算;
第(4)题,按运算顺序进行计算.
第(2)题,把除以5改成乘
1 |
5 |
第(3)题,运用乘法分配律简算;
第(4)题,按运算顺序进行计算.
解答:解:(1)
×
+
×
,
=(
+
)×
,
=4×
,
=5;
(2)
÷5+
×
,
=
×
+
×
,
=(
+
)×
,
=1×
,
=
;
(3)(
+
)×28,
=
×28+
×28,
=16+14,
=30;
(4)[1-(
+
)]÷
,
=[1-
]×7,
=
×7,
=1
.
5 |
4 |
5 |
2 |
5 |
4 |
3 |
2 |
=(
5 |
2 |
3 |
2 |
5 |
4 |
=4×
5 |
4 |
=5;
(2)
1 |
3 |
2 |
3 |
1 |
5 |
=
1 |
3 |
1 |
5 |
2 |
3 |
1 |
5 |
=(
1 |
3 |
2 |
3 |
1 |
5 |
=1×
1 |
5 |
=
1 |
5 |
(3)(
4 |
7 |
1 |
2 |
=
4 |
7 |
1 |
2 |
=16+14,
=30;
(4)[1-(
3 |
7 |
5 |
14 |
1 |
7 |
=[1-
11 |
14 |
=
3 |
14 |
=1
1 |
2 |
点评:此题考查学生四则混合运算的能力,在解答时注意审题,该简算的尽量要简算.
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