题目内容
(2008?江东区)
用递等式计算.(怎样算简便就怎样算) 5020-2940÷28×37 |
|
3×(
| ||||||||||||||||
|
1-
|
(0.25+
|
分析:(1)(3)(4)(5)(6)依据四则运算计算方法,先算第二级运算,再算第一级运算,如果只含有同一级运算,按照从左到右顺序计算,有括号先算括号里面的解答,
(2)运用乘法分配律解答.
(2)运用乘法分配律解答.
解答:解:(1)5020-2940÷28×37,
=5020-105×37,
=5020-3885,
=1135;
(2)
×0.25+
×
,
=
×(
+
),
=
×1,
=
;
(3)3×(
+
-
),
=3×(
-
),
=3×
,
=2
;
(4)
÷(
-
)×3,
=
÷
×3,
=7×3,
=21;
(5)1-
×(0.32+
),
=1-
×1.92,
=1-0.24,
=0.76;
(6)(0.25+
)+(
-
),
=
+
,
=1.1.
=5020-105×37,
=5020-3885,
=1135;
(2)
5 |
6 |
1 |
4 |
1 |
6 |
=
1 |
4 |
5 |
6 |
1 |
6 |
=
1 |
4 |
=
1 |
4 |
(3)3×(
7 |
12 |
5 |
9 |
1 |
4 |
=3×(
41 |
36 |
1 |
4 |
=3×
32 |
36 |
=2
2 |
3 |
(4)
7 |
2 |
7 |
6 |
2 |
3 |
=
7 |
2 |
1 |
2 |
=7×3,
=21;
(5)1-
1 |
8 |
8 |
5 |
=1-
1 |
8 |
=1-0.24,
=0.76;
(6)(0.25+
7 |
12 |
14 |
15 |
2 |
3 |
=
10 |
12 |
4 |
15 |
=1.1.
点评:本题主要考查学生依据四则运算计算方法解决问题的能力,如果算式有简便算法的,要正确选择并运用简便算法.
练习册系列答案
相关题目