题目内容
用递等式计算.
0.16+4÷(
|
1.7+3.98+5
|
4.8×3.9+6.1×4
|
分析:(1)先算小括号里面的,再算除法,最后求和;
(2)根据加法交换律进行计算;
(3)根据乘法分配律进行计算.
(2)根据加法交换律进行计算;
(3)根据乘法分配律进行计算.
解答:解:(1)0.16+4÷(
-
),
=0.16+4÷0.125,
=0.16+32,
=32.16;
(2)1.7+3.98+5
,
=1.7+3.98+5.3,
=1.7+5.3+3.98,
=7+3.98,
=10.98;
(3)4.8×3.9+6.1×4
,
=4.8×3.9+6.1×4.8,
=4.8×(3.9+6.1),、
=4.8×10,
=48.
3 |
8 |
1 |
4 |
=0.16+4÷0.125,
=0.16+32,
=32.16;
(2)1.7+3.98+5
3 |
10 |
=1.7+3.98+5.3,
=1.7+5.3+3.98,
=7+3.98,
=10.98;
(3)4.8×3.9+6.1×4
4 |
5 |
=4.8×3.9+6.1×4.8,
=4.8×(3.9+6.1),、
=4.8×10,
=48.
点评:本题主要考查了学生在四则运算中灵活运用简便算法的计算能力.
练习册系列答案
相关题目