题目内容
计算下列各题,能简便的要简便.
①0.25×4.78×4 | ②65×201 | ③17×23-23×7. |
分析:(1)运用乘法交换律解答,
(2)(3)运用乘法分配律解答.
(2)(3)运用乘法分配律解答.
解答:解:①0.25×4.78×4,
=0.25×4×4.78,
=1×4.78,
=4.78;
②65×201,
=65×(200+1),
=65×200+65×1,
=1300+65,
=1365;
③17×23-23×7,
=(17-7)×23,
=10×23,
=230.
=0.25×4×4.78,
=1×4.78,
=4.78;
②65×201,
=65×(200+1),
=65×200+65×1,
=1300+65,
=1365;
③17×23-23×7,
=(17-7)×23,
=10×23,
=230.
点评:解答此类题目,要注意分析算式中各数的关系,选择正确的简便算法.
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目