题目内容
用递等式计算(能巧算的要巧算).
(1)3956-(698+1956)
(2)97+98+103+102
(3)605-360÷12
(4)56+19×23.
(1)3956-(698+1956)
(2)97+98+103+102
(3)605-360÷12
(4)56+19×23.
分析:(1)先去括号,先算3956减去1956,再减去698.
(2)运用加法的交换律、结合律进行简算,
(3)先算除法,再算减法,
(4)先算乘法,再算加法.
(2)运用加法的交换律、结合律进行简算,
(3)先算除法,再算减法,
(4)先算乘法,再算加法.
解答:解:(1)3956-(698+1956),
=3956-1956-698,
=2000-698,
=1302;
(2)97+98+103+102,
=(97+103)+(98+102),
=200+200,
=400;
(3)605-360÷12,
=605-30,
=575;
(4)56+19×23,
=56+437,
=493.
=3956-1956-698,
=2000-698,
=1302;
(2)97+98+103+102,
=(97+103)+(98+102),
=200+200,
=400;
(3)605-360÷12,
=605-30,
=575;
(4)56+19×23,
=56+437,
=493.
点评:此题考查了整数四则混合运算的顺序,灵活运用运算定律进行简算即可.
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