题目内容

(2006?资中县)用递等式计算(能简算的请简算)
①4.68+14.79+5.32-10.79
②2.5×(6.8+6.8+6.8+6.8)
③475+238-147×3
④49.8+42÷15×4.5
⑤0.5×〔21.2÷(4.5+80%)〕
⑥(
7
9
+
1
3
)÷
8
15
〕×
3
10
分析:①运用加法交换律与结合律简算;
②括号内写成6.8×4,然后运用乘法交换律与结合律简算;
③先算乘法,再算加减;
④先算除法和乘法,再算加法;
⑤先算小括号内的,再算中括号内的,最后算括号外的;
⑥先算小括号内的,把除法改为乘法,去括号,约分计算.
解答:解:①4.68+14.79+5.32-10.79,
=(4.68+5.32)+(14.79-10.79),
=10+4,
=14;                
 
②2.5×(6.8+6.8+6.8+6.8),
=2.5×(6.8×4),
=2.5×6.8×4,
=(2.5×4)×6.8,
=10×6.8,
=68;

③475+238-147×3,
=475+238-441,
=713-441,
=272;

④49.8+42÷15×4.5,
=49.8+2.8×4.5,
=49.8+12.6,
=62.4;

⑤0.5×[21.2÷(4.5+80%)],
=0.5×[21.2÷5.3],
=0.5×4,
=2;

⑥[(
7
9
+
1
3
)÷
8
15
3
10

=[
10
9
×
15
8
3
10

=
10
9
×
15
8
×
3
10

=
5
8
点评:此题考查了小数、分数的四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算.
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