题目内容

计算.
(1)1.25×17.6+36.1÷0.8+2.63×12.5
(2)(78.6-0.786×25十75%×21.4)÷15×2011.

解:(1)1.25×17.6+36.1÷0.8+2.63×12.5,
=1.25×17.6+36.1÷+26.3×1.25,
=1.25×17.6+36.1×1.25+26.3×1.25,
=(17.6+36.1+26.3)×12.5,
=80×1.25,
=100;

(2)(78.6-0.786×25+75%×21.4)÷15×2011,
=(78.6-0.786×25+×21.4)÷15×(2000+11),
=(78.6-0.786×100×+×21.4)÷15×(2000+11),
=(78.6-78.6×+×21.4)÷15×(2000+11),
=[78.6×(1-)+×21.4]÷15×(2000+11),
=[78.6×+×21.4]÷15×(2000+11),
=[(78.6+21.4)×]÷15×(2000+11),
=[100×]÷15×(2000+11),
=75÷15×(2000+11)
=5×(2000+11),
=10000+55,
=10055.
分析:(1)根据数字特点,把原式变为1.25×17.6+36.1÷+26.3×1.25,即1.25×17.6+36.1×1.25+26.3×1.25,然后运用乘法分配律简.
(2)根据数字特点,可将算式改写成(78.6-0.786×25+×21.4)÷15×(2000+11),再把25写成100×,运用乘法分配律进行计算.
点评:此题主要考查是的小数的四则混合运算和简便运算,这两题在计算时,充分利用了乘法分配律.
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