题目内容
用递等式计算.
8.56+(100-90.25)÷5 425+75×
÷
18÷[
+(
-
)].
8.56+(100-90.25)÷5 425+75×
3 |
5 |
3 |
4 |
5 |
6 |
5 |
8 |
1 |
3 |
分析:(1)按运算顺序计算,先算括号内的,再算括号外的除法,最后算括号外的加法;
(2)把除法改为乘法,先算乘法,再算加法;
(3)按运算顺序计算,先算小括号内的减法,再算中括号内的加法,最后算括号外的除法.
(2)把除法改为乘法,先算乘法,再算加法;
(3)按运算顺序计算,先算小括号内的减法,再算中括号内的加法,最后算括号外的除法.
解答:解:(1)8.56+(100-90.25)÷5,
=8.56+9.75÷5,
=8.56+1.95,
=10.51;
(2)425+75×
÷
,
=425+75×
×
,
=425+60,
=485;
(3)18÷[
+(
-
)],
=18÷[
+(
-
)],
=18÷[
+
],
=18÷
,
=18×
,
=16.
=8.56+9.75÷5,
=8.56+1.95,
=10.51;
(2)425+75×
3 |
5 |
3 |
4 |
=425+75×
3 |
5 |
4 |
3 |
=425+60,
=485;
(3)18÷[
5 |
6 |
5 |
8 |
1 |
3 |
=18÷[
5 |
6 |
15 |
24 |
8 |
24 |
=18÷[
20 |
24 |
7 |
24 |
=18÷
27 |
24 |
=18×
24 |
27 |
=16.
点评:此题重点考查学生对四则混合运算顺序的掌握,以及计算能力.
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