题目内容
递等式计算(能简算的要简算) ①(8.5-4)×10.32÷16 |
②
|
③42×101-42 | ||||||||
④(
|
⑤7.6-1.26-1.74 | ⑥(4.2-3.52÷1.6)×1.5. |
分析:①②题,按运算顺序计算,从左向右依次计算;
③把101看作100+1,运用乘法分配律简算;
④根据数字特点,运用乘法分配律简算;
⑤根据减法的性质,进行简算;
⑥按运算顺序计算,先算括号内的除法,再算括号内的减法,最后算括号外的.
③把101看作100+1,运用乘法分配律简算;
④根据数字特点,运用乘法分配律简算;
⑤根据减法的性质,进行简算;
⑥按运算顺序计算,先算括号内的除法,再算括号内的减法,最后算括号外的.
解答:解:①(8.5-4)×10.32÷16,
=4.5×10.32÷16,
=46.44÷16,
=2.9025;
②
×(
÷
+
),
=
×(
×
+
),
=
×(
+
),
=
×(
+
),
=
×
,
=
;
③42×101-42,
=(101-1)×42,
=100×42,
=4200;
④(
+
-
)×72,
=
×72+
×72-
×72,
=30+8-27,
=11;
⑤7.6-1.26-1.74,
=7.6-(1.26+1.74),
=7.6-3,
=4.6;
⑥(4.2-3.52÷1.6)×1.5,
=(4.2-2.2)×1.5,
=2×1.5,
=3.
=4.5×10.32÷16,
=46.44÷16,
=2.9025;
②
4 |
9 |
3 |
10 |
3 |
5 |
2 |
5 |
=
4 |
9 |
3 |
10 |
5 |
3 |
2 |
5 |
=
4 |
9 |
1 |
2 |
2 |
5 |
=
4 |
9 |
5 |
10 |
4 |
10 |
=
4 |
9 |
9 |
10 |
=
2 |
5 |
③42×101-42,
=(101-1)×42,
=100×42,
=4200;
④(
5 |
12 |
1 |
9 |
3 |
8 |
=
5 |
12 |
1 |
9 |
3 |
8 |
=30+8-27,
=11;
⑤7.6-1.26-1.74,
=7.6-(1.26+1.74),
=7.6-3,
=4.6;
⑥(4.2-3.52÷1.6)×1.5,
=(4.2-2.2)×1.5,
=2×1.5,
=3.
点评:此题考查了学生用递等式计算的能力,掌握运算顺序、运算定律是解答此题的关键.
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