摘要:A.B点的横座标a==12.5.且有c(Na+)==c(CH3COO―)B.C点时.c(CH3COO―)>c(Na+)>c(H+)= c(OH―)C.D点时.c(CH3COO―)+ c(CH3COOH)==2c(Na+)D.对曲线上A.B间任何一点.溶液中都有:c(Na+)>c(CH3COO―)>c(OH―) >c(H+)[解析]A不对,因二者刚好反应时,由于生成物水解,溶液呈碱性,故c(Na+)不等于c(CH3COO―),B不对,当c(H+)= c(OH―)时,根据电荷守恒c(Na+)==c(CH3COO―),C正确,根据物料守恒,D不对,初始阶段 c(OH―) > c(CH3COO―)[答案]C
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