摘要:1.已知等比数列{an}满足a1+a2=3.a2+a3=6.则a7=( ) A.64 哀14d-B.81 C.128 D.243 答案:A 解析:∵{an}是等比数列.∴=q==2.又∵a1+a1q=3.∴a1=1.∴a7=a1q6=26=64.故选A.

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