摘要:C. D.
网址:http://m.1010jiajiao.com/timu_id_321192[举报]
C
[解析] 由基本不等式,得ab≤
=
=
-ab,所以ab≤
,故B错;
+
=
=
≥4,故A错;由基本不等式得
≤
=
,即
+
≤
,故C正确;a2+b2=(a+b)2-2ab=1-2ab≥1-2×
=
,故D错.故选C.
网址:http://m.1010jiajiao.com/timu_id_321192[举报]
C
[解析] 由基本不等式,得ab≤
=
=
-ab,所以ab≤
,故B错;
+
=
=
≥4,故A错;由基本不等式得
≤
=
,即
+
≤
,故C正确;a2+b2=(a+b)2-2ab=1-2ab≥1-2×
=
,故D错.故选C.