摘要:∴OD//PA.又PA平面PAB.∴OD//平面PAB.(2)∵AB⊥BC.OA=OC∴OA=OC=OB.又∵OP⊥平面ABC.∴PA=PB=PC取BC中点E.连结PE.则BC⊥平面POE.作OF⊥PE于F.连结OF.则OF⊥平面PBC.
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( I)求证:OD∥平面PAB;
( II)求PB与平面ABC所成角.
![](http://thumb.zyjl.cn/pic3/upload/images/201310/45/9605dcd9.png)
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(I)证明平面PAB⊥平面ABC;
(Ⅱ)求直线PB与平面PAC所成角的正弦值.
![](http://thumb.zyjl.cn/pic3/upload/images/201305/35/6bfbecdc.png)
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(Ⅰ)求证:BD⊥PC;
(Ⅱ)求证:MN∥平面PDC;
(Ⅲ)设平面PAB∩平面PCD=l,试问直线l是否与直线CD平行,请说明理由.