摘要: (1)425.6···························· (2)y=(176x+24)×22.4 m3········· 图像如右图:····················· (3)解一:设窑气为100 mol.则n(N2)=100-41.6-0.2-0.2=58 mol.总共有n(O2)=58/4=14.5 mol,故参加反应的n(O2)=14.5 mol-0.2 mol=14.3 mol, 2C + O2 = 2CO C + O2 = CO2 CaCO3=CO2↑+CaO 2 1 2 1 1 1 1 1

网址:http://m.1010jiajiao.com/timu3_id_60284[举报]

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网