摘要:化学反应N2+3H2=2NH3的能量变化如题图所示.该反应的热化学方程式是( ) A.N2(g)+3H2(g)=2NH3(1); △H=2kJ·mol-1 B. N2(g)+3H2(g)=2NH3(g); △H=2(b-a)kJ·mol-1 C.N2(g)+H2(g)=NH3(1); △H=kJ·mol-1 D. N2(g)+H2(g)=NH3(g); △H=(a+b)kJ·mol-1

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