摘要: 设数列{an}和{bn}满足a1=b1=6.a2=b2=4.a3=b3=3.且数列{an+1-an}是等差数列.数列{bn-2} 是等比数列. (1)设Cn=an+1-an.求数列{Cn}的通项公式 (2)求数列{an}和{bn}的通项公式. =an-bn.当n≥4时.试判断f(n)的增减性.
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(本小题满分14分)设数列{an}和{bn}满足a1=b1=6,a2=b2=4,a3=b3=3,且数列{an+1-an}是等差数列,数列{bn―2}是等比数列(n∈N*).
(Ⅰ)求数列{an},{bn}的通项公式;
(Ⅱ)是否存在k∈N*,使
?若存在,求出k,若不存在,说明理由.