摘要:化学反应N2+3H2 =2NH3的能量变化如右图所示.该反应的热化学方程式可以写作( ) A. N2(g)+3H2(g) =2NH3(l) ΔH =2 kJ·mol-1 B. N2(g)+3H2(g) =2NH3(g) ΔH =2 kJ·mol-1 C. 1/2N2(g)+3/2H2(g) =NH3(l) ΔH = kJ·mol-1 D. 1/2N2(g)+3/2H2(g) =NH3 kJ·mol-1

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