题目内容
(6分)矿井里的升降机从静止开始做匀加速直线运动,上升3s,速度达到3m/s,然后匀速上升6s,最后减速上升2s停下,升降机上升的高度为________,在方框中画出升降机运动的v一t图像。
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115535966829.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115535966829.png)
25.5(m)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241155360282928.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241155360282928.png)
矿井里的升降机运动的速度-时间图象如图所示
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241155360282928.png)
如图示,v—t图像求高度,图像所围成的面积数值上等于位移的大小
S=S梯=
=25.5(m)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241155360282928.png)
如图示,v—t图像求高度,图像所围成的面积数值上等于位移的大小
S=S梯=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115536278683.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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