题目内容
如图所示,半径为R、圆心角为60?的光滑圆弧槽,固定在高为h的平台上,小物块从圆 弧槽的最高点A静止开始滑下,滑出槽口 B时速度水平向左,小物块落在地面上C点, B、C两点在以O2点为圆心的圆弧上,02在B点正下方地面上,则
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250012119203699.jpg)
A.4R=h B.2R=h
C.R=h D.R=2h
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250012119203699.jpg)
A.4R=h B.2R=h
C.R=h D.R=2h
B
试题分析:物体由A到B由动能定理有:mgR(1- cos60?)=
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001211998627.png)
竖直方向h=
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001212013541.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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