ÌâÄ¿ÄÚÈÝ
Èçͼ¼×Ëùʾ£¬¿Õ¼ä´æÔÚÒ»¿í¶ÈΪ2LÓнçÔÈÇ¿´Å³¡£¬´Å³¡·½Ïò´¹Ö±Ö½ÃæÏòÀï¡£Ôڹ⻬¾øԵˮƽÃæÄÚÓÐÒ»±ß³¤ÎªLµÄÕý·½ÐνðÊôÏß¿ò£¬ÆäÖÊÁ¿m=1kg¡¢µç×èR=4¦¸£¬ÔÚˮƽÏò×óµÄÍâÁ¦F×÷ÓÃÏ£¬ÒÔ³õËÙ¶Èv0=4m/sÔȼõËÙ½øÈë´Å³¡£¬Ïß¿òƽÃæÓë´Å³¡´¹Ö±£¬ÍâÁ¦F´óСËæʱ¼ät±ä»¯µÄͼÏßÈçͼÒÒËùʾ¡£ÒÔÏß¿òÓұ߸սøÈë´Å³¡Ê±¿ªÊ¼¼Æʱ£¬Çó£º
£¨1£©ÔÈÇ¿´Å³¡µÄ´Å¸ÐӦǿ¶ÈB£»
£¨2£©Ïß¿ò½øÈë´Å³¡µÄ¹ý³ÌÖУ¬Í¨¹ýÏß¿òµÄµçºÉÁ¿q£»
£¨3£©ÅжÏÏß¿òÄÜ·ñ´ÓÓÒ²àÀ뿪´Å³¡£¿ËµÃ÷ÀíÓÉ¡£
£¨1£©ÔÈÇ¿´Å³¡µÄ´Å¸ÐӦǿ¶ÈB£»
£¨2£©Ïß¿ò½øÈë´Å³¡µÄ¹ý³ÌÖУ¬Í¨¹ýÏß¿òµÄµçºÉÁ¿q£»
£¨3£©ÅжÏÏß¿òÄÜ·ñ´ÓÓÒ²àÀ뿪´Å³¡£¿ËµÃ÷ÀíÓÉ¡£
£¨1£©0.33T£¨2£©0.75C (3)²»ÄÜ
ÊÔÌâ·ÖÎö£º
£¨1£©ÓÉF-tͼÏñ¿ÉÖª£¬1sºóÏßȦȫ²¿½øÈë´Å³¡£¬ÏßȦֻÊÜÍâÁ¦×÷Ó㬿ÉÇóÆäÏß¿ò¼ÓËÙ¶È
Ïß¿òµÄ±ß³¤ =3m
t=0ʱ¿ÌÏß¿òÖеĸÐÓ¦µçÁ÷
Ïß¿òÊܵݲÅàÁ¦F°²=BIL
ÓÉÅ£¶ÙµÚ¶þ¶¨ÂÉ F1+F°²=ma
ÓÖF1=1N,ÁªÁ¢µÃB=1/3T=0.33T
(2)Ïß¿ò½øÈë´Å³¡µÄ¹ý³ÌÖУ¬Æ½¾ù¸ÐÉúµç¶¯ÊÆ
ƽ¾ùµçÁ÷
ͨ¹ýÏß¿òµÄµçºÉÁ¿Îª=0.75C
(3)ÉèÔȼõËÙÔ˶¯ËٶȼõΪÁãʱµÄλÒÆΪx
ÓÉÔ˶¯Ñ§¹«Ê½µÃ
´øÈëÊýÖµµÃ x=4m£¼2L
ËùÒÔÏß¿ò²»ÄÜ´ÓÓÒ²àÀ뿪´Å³¡¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿