ÌâÄ¿ÄÚÈÝ

ÓÐA¡¢B¡¢C¡¢D¡¢EÎåλͬѧ×ö¡°Óõ¥°Ú²â¶¨ÖØÁ¦¼ÓËٶȡ±µÄʵÑ飬ʵÑéÊý¾ÝÁÐÓÚÏÂ±í£¬Èôÿλͬѧ¶¼ÄÜÕýȷʹÓÃÒÇÆ÷²âÁ¿£¬Ôò£º
ͬѧ °ÚÇò²ÄÁÏ ×î´ó°Ú½Ç °Ú³¤/m È«Õ𶯴ÎÊý Ëù²âʱ¼ä/s
A ľ 5¡ã 0.41 10 23.6
B ÂÁ 4¡ã 0.50 50 87.2
C Ìú 4¡ã 0.80 50 90.0
D Í­ 15¡ã 0.60 30 70.8
E Ǧ 20¡ã 0.80 30 71.8
¢Ù
 
ͬѧµÄ²âÁ¿½á¹û¸ü׼ȷ
¢ÚÓɴ˼ÆËã³öµÄÖØÁ¦¼ÓËٶȵĴóСΪ
 
m/s2£¨×îºó½á¹û±£ÁôÈýλÓÐЧÊý×Ö£©£®
·ÖÎö£ºµ¥°ÚʵÑéµÄ¾«È·¶ÈÈ¡¾öÓÚʵÑé×°ÖõÄÀíÏ뻯³Ì¶È¼°Ïà¹ØÎïÀíÁ¿µÄ²âÁ¿¾«¶È£¬Êʵ±¼Ó´ó°ÚÏß³¤¶È£¬ÓÐÀûÓÚ°Ñ°ÚÇò¿´³ÉÖʵ㣬ÔÚ°ÚÇòСÓÚ5¡ã×óÓÒµÄÌõ¼þÏ£¬°ÚÇò¿Õ¼äλÖñ仯½Ï´ó£¬±ãÓڹ۲죻°ÚÇòÖÊÁ¿¹ý´ó£¬ËùÊÜ¿ÕÆø×èÁ¦Ô½´ó£¬×ۺϷÖÎö¿ÉÅжϣ»
¸ù¾Ýµ¥°ÚµÄÖÜÆÚ¹«Ê½T=2¦Ð
L
g
£¬¿ÉµÃ£ºg=
4¦Ð2L
T2
£¬¿ÉÇóµÃ¼ÓËÙ¶È
½â´ð£º½â£ºµ¥°ÚʵÑéµÄ¾«È·¶ÈÈ¡¾öÓÚʵÑé×°ÖõÄÀíÏ뻯³Ì¶È¼°Ïà¹ØÎïÀíÁ¿µÄ²âÁ¿¾«¶È£¬Êʵ±¼Ó´ó°ÚÏß³¤¶È£¬ÓÐÀûÓÚ°Ñ°ÚÇò¿´³ÉÖʵ㣬ÔÚ°ÚÇòСÓÚ5¡ãµÄÌõ¼þÏ£¬°ÚÇò¿Õ¼äλÖñ仯½Ï´ó£¬±ãÓڹ۲죻°ÚÇòÖÊÁ¿¹ý´ó£¬ËùÊÜ¿ÕÆø×èÁ¦Ô½´ó£¬¹Ê×ۺϷÖÎö£¬Cͬѧ²âÁ¿µÄ½á¹û¸ü׼ȷ£»
¸ù¾Ýµ¥°ÚÖÜÆÚ¹«Ê½£ºT=2¦Ð
L
g
£¬
¿ÉµÃ£ºg=
4¦Ð2L
T2

ÓÖT=
t
n

´úÈëCͬѧ²âÁ¿µÄÊý¾Ý£¬½âµÃ£ºg=9.74m/s2
¹Ê´ð°¸Îª£º¢ÙC£»¢Ú9.74
µãÆÀ£º±¾Ì⿼²éµ¥°ÚʵÑ飬¸ù¾ÝʵÑéÔ­ÀíÑ¡ÔñʵÑé×°Öã¬Äܹ»¸ù¾Ýµ¥°ÚÖÜÆÚ¹«Ê½£¬¼ÆËãÖØÁ¦¼ÓËٶȣ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø