ÌâÄ¿ÄÚÈÝ

15£®Ä³Í¬Ñ§ÀûÓÃͼ£¨a£©ËùʾµÄʵÑé×°ÖÃ̽¾¿Îï¿éËÙ¶ÈËæʱ¼äµÄ±ä»¯£®Îï¿é·ÅÔÚ×ÀÃæÉÏ£¬Ï¸ÉþµÄÒ»¶ËÓëÎï¿éÏàÁ¬£¬ÁíÒ»¶Ë¿ç¹ý»¬ÂÖ¹ÒÉϹ³Â룮´òµã¼ÆʱÆ÷¹Ì¶¨ÔÚ×ÀÃæ×ó¶Ë£¬ËùÓý»Á÷µçԴƵÂÊΪ50Hz£®Ö½´ø´©¹ý´òµã¼ÆʱÆ÷Á¬½ÓÔÚÎï¿éÉÏ£®Æô¶¯´òµã¼ÆʱÆ÷£¬ÊÍ·ÅÎï¿é£¬Îï¿éÔÚ¹³ÂëµÄ×÷ÓÃÏÂÍÏ×ÅÖ½´øÔ˶¯£®´òµã¼ÆʱÆ÷´ò³öµÄÖ½´øÈçͼ£¨b£©Ëùʾ£¨Í¼ÖÐÏàÁÚÁ½µã¼äÓÐ4¸öµãδ»­³ö£©£®

¸ù¾ÝʵÑéÊý¾Ý·ÖÎö£¬¸ÃͬѧÈÏΪÎï¿éµÄÔ˶¯ÎªÔȼÓËÙÔ˶¯£®»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÏàÁÚ¼ÆÊýµãµÄʱ¼ä¼ä¸ôT=0.1s£¬ÔÚ´òµã¼ÆʱÆ÷´ò³öBµãʱ£¬Îï¿éµÄËٶȴóСΪ0.56m/s£®£¨±£ÁôÁ½Î»ÓÐЧÊý×Ö£©
£¨2£©Îï¿éµÄ¼ÓËٶȴóСΪ2.0m/s2£®£¨±£ÁôÁ½Î»ÓÐЧÊý×Ö£©

·ÖÎö ¸ù¾ÝÏàÁÚÁ½µã¼äÓÐ4¸öµãδ»­³ö£¬¼´¿ÉÈ·¶¨ÏàÁÚ¼ÆÊýµãʱ¼ä¼ä¸ô£»
×öÔȱäËÙÖ±ÏßÔ˶¯µÄÎïÌåÔÚij¶Îʱ¼äÄÚµÄƽ¾ùËٶȵÈÓڸöÎʱ¼äÖмäʱ¿ÌµÄ˲ʱËٶȣ¬Çó³ö˲ʱËٶȣ»
ÔÚÏàÁÚµÄÏàµÈʱ¼ä¼ä¸ôÄÚµÄλÒƲîÊǶ¨Öµ£¬¡÷x=at2£¬¾Ý´Ë¿ÉÇóµÃ¼ÓËٶȣ®

½â´ð ½â£º£¨1£©Í¼ÖÐÏàÁÚÁ½µã¼äÓÐ4¸öµãδ»­³ö£¬Òò´ËÏàÁÚ¼ÆÊýµãµÄʱ¼ä¼ä¸ôT=0.1s£¬
xAC=£¨4.61+6.59£©cm=£¨4.61+6.59£©¡Á10-2 m£»
´òBµãʱС³µËÙ¶ÈΪ£ºvB=$\frac{{x}_{AC}}{2T}$=$\frac{4.61+6.59}{2¡Á0.1}¡Á1{0}^{-2}$m/s=0.56m/s£»
£¨2£©xCE-xAC=£¨£¨8.61+10.61£©-£¨4.61+6.59£©£©cm=£¨£¨8.61+10.61£©-£¨4.61+6.59£©£©¡Á10-2 m£»
С³µµÄ¼ÓËÙ¶ÈΪ£ºa=$\frac{{x}_{CE}-{x}_{AC}}{4{T}^{2}}$=$\frac{8.61+10.61-£¨4.61+6.59£©}{4¡Á0£®{1}^{2}}¡Á1{0}^{-2}$ m/s2=2.0m/s2£»
¹Ê´ð°¸Îª£º£¨1£©0.1£¬0.56£»£¨2£©2.0£®

µãÆÀ ±¾Ì⿼²éÁËÇó˲ʱËÙ¶ÈÓë¼ÓËÙ¶ÈÎÊÌ⣬ÊìÁ·Ó¦ÓÃÔȱäËÙÔ˶¯µÄÍÆÂÛ¼´¿ÉÕýÈ·½âÌ⣬עÒâÓÐЧÊý×ֵı£Áô£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø