ÌâÄ¿ÄÚÈÝ

12£®ÈçͼËùʾ£¬M£¬NÁ½¼«°å¼ä´æÔÚÔÈÇ¿µç³¡£¬Á½¼«°åµÄ¿í¶ÈΪd£¬N°åÓұߴæÔÚÈçͼËùʾµÄ´Å³¡£¬ÕÛÏßPAQÊǴų¡µÄ·Ö½çÏߣ¬ÔÚÕÛÏßµÄÁ½²à·Ö²¼×Å·½ÏòÏà·´¡¢ÓëƽÃæ´¹Ö±µÄÔÈÇ¿´Å³¡£¬´Å¸ÐӦǿ¶È´óС¶¼ÎªB£®ÕÛÏߵĶ¥½Ç¡ÏA=90¡ã£¬P¡¢QÊÇÕÛÏßÉϵÄÁ½µã£¬AP=AQ=L£®ÏÖÓÐÒ»ÖÊÁ¿Îªm¡¢µçºÉÁ¿ÎªqµÄ´ø¸ºµç΢Á£´ÓSÓɾ²Ö¹¾­µç³¡¼ÓËÙºóÔÙ´ÓPµãÑØPQ·½ÏòˮƽÉä³ö£¬²»¼Æ΢Á£µÄÖØÁ¦£®
£¨1£©Èô΢Á£ÒÔv0µÄËٶȴÓPµãÉä³ö£¬ÇóM£¬NÁ½¼«°å¼äµç³¡Ç¿¶ÈµÄ´óС¼°·½Ïò£»
£¨2£©ÎªÊ¹Î¢Á£´ÓPµãÒÔijһËÙ¶ÈvÉä³öºó£¬¾­¹ýÒ»´Îƫתֱ½Óµ½´ïÕÛÏߵĶ¥µãAµã£¬Çó³õËÙ¶ÈvµÄ´óС£»
£¨3£©¶ÔÓÚÔÚM£¬NÁ½¼«°å¼ä¼Ó²»Í¬µÄµç³¡£¬Î¢Á£»¹ÄÜ;¾­Aµã²¢Äܵ½´ïQµã£¬ÇóËù¼Óµç³¡µÄµç³¡Ç¿¶ÈEÓ¦Âú×ãµÄÌõ¼þ¼°Æä´ÓPµãµ½´ïQµãËùÓõÄʱ¼ä£®

·ÖÎö £¨1£©¸ù¾Ýµç³¡Á¦ÓëÂåÂ××ÈÁ¦Æ½ºâ£¬¼´¿ÉÇó½â£»
£¨2£©¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂÉ£¬ÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦£¬½áºÏ¼¸ºÎ¹Øϵ£¬¼´¿ÉÇó½â£»
£¨3£©ÓÉnÈ¡ÆæÊýÓëżÊýÁ½ÖÖÇé¿öÏ£¬½áºÏÔ²ÐĽǣ¬´Ó¶øÇó³öʱ¼ä£®

½â´ð ½â£º£¨1£©ÔÚM£¬N¼äÓɶ¯Äܶ¨Àí£ºqEd=$\frac{1}{2}m{v}_{0}^{2}$   
µÃ£º$E=\frac{m{v}_{0}^{2}}{2qd}$£¬·½ÏòÏò×ó£»
  
£¨2£©ÓÉͼÖм¸ºÎ¹ØϵµÃ£º
2Rsin45¡ã=L  
µÃ£ºR=$\frac{L}{\sqrt{2}}$
ÓÉqvB=m$\frac{{v}^{2}}{R}$
µÃ£ºv=$\frac{\sqrt{2}qBL}{2m}$£»
    
£¨3£©¸ù¾ÝÔ˶¯¶Ô³ÆÐÔ£¬Î¢Á£ÄÜ´ÓPµãµ½´ïQµã£¬Ó¦Âú×ãL=nx£¬ÆäÖÐxΪÿ´ÎƫתԲ»¡¶ÔÓ¦ÏÒ³¤£¬Æ«×ªÔ²»¡¶ÔÓ¦Ô²ÐĽÇΪ90¡ã»ò270¡ã£¬
ÉèÔ²»¡³¤ÎªR£¬ÔòÓÐ2R2=x2£¬¿ÉµÃ£ºR=$\frac{\sqrt{2}L}{2n}$£¬
ÓÖqvB=m$\frac{{v}^{2}}{R}$£¬
µÃ£ºv=$\frac{2qBL}{2mn}$£¬£¨n=1¡¢2¡¢3¡¢¡­£©  
ÓÉ$qEd=\frac{1}{2}m{v}^{2}$
µÃ$E=\frac{{B}^{2}q{L}^{2}}{4dm{n}^{2}}$£¨n=1¡¢2¡¢3¡¢¡­£© 
µ±nÈ¡ÆæÊýʱ£¬Î¢Á£´ÓPµ½Q¹ý³ÌÖÐÔ²ÐĽÇ×ܺÍΪ£ºÎª
${¦È}_{1}=n•\frac{¦Ð}{2}+n•\frac{3¦Ð}{2}=2n¦Ð$
${t}_{1}=2n¦Ð•\frac{m}{qB}=\frac{2¦Ðm}{qB}•n$£¬ÆäÖÐn=1¡¢3¡¢5¡¢¡­
µ±nȡżÊýʱ£¬Î¢Á£´ÓPµ½Q¹ý³ÌÖÐÔ²ÐĽÇ×ܺÍΪ
${¦È}_{2}=n•\frac{¦Ð}{2}+n•\frac{¦Ð}{2}=n¦Ð$£¬
${t}_{2}=n¦Ð•\frac{m}{qB}=\frac{¦Ðm}{qB}•n$£¬ÆäÖÐn=2¡¢4¡¢6¡¢¡­
´ð£º£¨1£©µç³¡Ç¿¶ÈµÄ´óСΪ$\frac{m{v}_{0}^{2}}{2qd}$£¬·½ÏòΪÏò×ó£»
£¨2£©³õËÙ¶ÈvµÄ´óСΪ$\frac{\sqrt{2}qBL}{2m}$£»
£¨3£©Î¢Á£µÄ³õËÙ¶ÈvÓ¦Âú×ãµÄÌõ¼þÊÇ$\frac{qBL}{\sqrt{2}mn}$£¬£¨n=1¡¢2¡¢3¡¢¡­£©£»
µ±nÈ¡ÆæÊýʱ£¬´ÓPµãµ½´ïQµãËùÓõÄʱ¼ä${t}_{1}=2n¦Ð•\frac{m}{qB}=\frac{2¦Ðm}{qB}•n$£¬ÆäÖÐn=1¡¢3¡¢5¡¢¡­£»
µ±nȡżÊýʱ£¬´ÓPµãµ½´ïQµãËùÓõÄʱ¼ä${t}_{2}=n¦Ð•\frac{m}{qB}=\frac{¦Ðm}{qB}•n$£¬ÆäÖÐn=2¡¢4¡¢6¡¢¡­

µãÆÀ ±¾Ì⿼²é´øµçÁ£×ÓÔÚ×éºÏ³¡ÖеÄÔ˶¯£¬¹Ø¼üÊÇÒªÃ÷È·Á£×Ó¸÷¸ö½×¶ÎµÄÔ˶¯¹æÂÉ£¬¶Ô¸÷¸ö¹ý³ÌÄÜÊìÁ·µØÑ¡ÓÃÏàÓ¦µÄ¹æÂÉÁÐʽ¼ÆË㣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø